Q(r)=3r^2-15+18

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Solution for Q(r)=3r^2-15+18 equation: 



(Q)=3Q^2-15+18

We move all terms to the left:

(Q)-(3Q^2-15+18)=0

We get rid of parentheses

-3Q^2+Q+15-18=0

We add all the numbers together, and all the variables

-3Q^2+Q-3=0

a = -3; b = 1; c = -3;
Δ = b2-4ac
Δ = 12-4·(-3)·(-3)
Δ = -35
Delta is less than zero, so there is no solution for the equation

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